For the function f(x)=x^2-8x-20 determine whether the graph opens up or down, find the axis of symmetry, find the vertex, find the y intercept, find the x intercept, and graph the function. Please Help Thank You
Since coefficient of x^2 is 1 (positive), it opens up.
Axis of symmetry : x=4
vertex = (4,-36)
By solving x^2-8x-20= x^2-10x+2x-20= x(x-10)+2(x-10) =(x-10)(x+2)
x intercept is -2, and 10
y intercept is -20
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