For the function f(x)=x^2-8x-20 find the following

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For the function f(x)=x^2-8x-20 determine whether the graph opens up or down, find the axis of symmetry, find the vertex, find the y intercept, find the x intercept, and graph the function. Please Help Thank You

Nov 13th, 2014

Since coefficient of x^2 is 1 (positive), it opens up.

(y+36)=(x-4)^2

Axis of symmetry : x=4

vertex = (4,-36)

By solving x^2-8x-20= x^2-10x+2x-20= x(x-10)+2(x-10) =(x-10)(x+2)

x intercept is -2, and 10

y intercept is -20

parabola_nov13.xlsx 


Nov 13th, 2014

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Nov 13th, 2014
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Nov 13th, 2014
Jun 23rd, 2017
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