Use completing the square to write f(x)=x^2+3x-18 in vertex form. What is the vertex for the function and how can you confirm the vertex

f(x)=x^{2}+3x-18

=x^{2}+2*x*3/2+9/4 -18-9/4

= (x+3/2)^{2}-81/4

(y+81/4) = (x+3/2))^{2}

y'= x'^2

Vertex (-3/2, -81/4)

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