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product of 2 consecutive positive integers is 11 more than their sum.  find integers.

Nov 14th, 2014

Let two integers be x and another as (x+1) as its consecutive .

x(x+1)=11

x^2+x-11=0

x=(-1+-√(1+44))/2=(-1+-√45)/2

Add x+1=1+(-1+-√45)/2=(1+-√45)/2

Nov 14th, 2014

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Nov 14th, 2014
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Nov 14th, 2014
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