a chemist mixed x milliliters of 25% acid solution with some 15% acid solution to produce 100 milliliters of a 19% acid solution.

We need to set up a table to solve this mixture problem.

mL of acid % acid total mL acid

25% sol'n x 0.25 0.25x

15% sol'n y 0.15 0.15y

Mixture x+y = 100 0.19 0.19(100) = 19

Since we know that x + y = 100, we can solve for x = 100 - y. Now substitute this into the table:

25% sol'n 100-y 0.25 0.25(100-y)

Mixture 100 0.19 0.19(100) = 19

Now we can take the last column and solve:

0.25(100-y) + 0.15y = 19

25 - 0.25y + 0.15y = 19

-0.25y + 0.15y = -6

-0.10y = -6

y = 60 mL

Since we know that x + y = 100:

x+60 = 100

x = 40 mL

Therefore, you need 40 mL of 25% acid solution and 60 mL of 15% solution.

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