...with mean on 100 and S.D. of 15

A. What is the probability that a random sample of 36 individuals will have an average IQ greater than 103?

B. What is the probability that a random sample of 100 individuals will have an average IQ greater than 10

P (average IQ> 103 | mean =100, Standard error = 15/6 =2.5)=0.1151

z= (103-100)/2.5 =1.2

P (average IQ> 103 | mean =100, Standard error = 15/10 =1.5)=0.0228

z= (103-100)/1.5 =2

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