the question is : f(x)=x^2-4x+9
how would i do this step by step? big test tomorrow
You have not written what you have to do.
I am supposing you want to sketch the function/ find minimum value
f(x) = (x^2-4x+4+ 5
= (x -2)^2 + 5
this has a minimum value of 5 at x=2
To sketch at plot the vertex point (2,5) and also the point (0,9)
basically it will look like f(x) -=x^2 but translated (shifted) so that the vertex is at (2,5) rather than (0,0)
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