based on the equation above, write conversion factors for moles of reactant to moles of the other reactant and each product.
2C8H18(l) + 25O2 16CO2(g) + 18H2O(g)
From the equation, 16 moles of CO2 (a greenhouse gas resulting in global warming) are
produced for every 2 moles of octane burned (by combustion).
Estimate the mass of CO2 produced in 2004 by the combustion of 3.4 x 1015 g gasoline.
Solution: number of moles = mass/molar mass; molar mass = molecular mass
molecular masses: C8H18 = 114.22; CO2 = 44.01 gmol-1
3.4 x 1015/114.22 = 2.977 x 1013 moles C8H18.
stoichiometric ratio CO2: C8H18 = 16:2 2.977x 1013 x (16/2) = 2.382 x 1014 moles CO2
= 1.05 x 1016 g CO2.
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