Find Speed of Light in Water Using Index of Refraction of Water Found in This Lab

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please help with lab 11 on physics due next week thank you please carefull do

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Explanation & Answer

The final answer is attached

Physics 2 Lab

Questions
1. Find the speed of light in water using the index of refraction of water found in this lab.
2. List possible sources of error.
Data Sheet: Refraction
Part I: Air to Water
𝜽𝒊

𝜽𝒓

56
43
41
26
15
10
86
64
71
77

𝐬𝐢𝐧(𝜽𝒊 )

39
31
28
19
11
7
48
43
45
47

0.829
0.682
0.656
0.438
0.258
0.174
0.997
0.899
0.945
0.974

𝐬𝐢𝐧(𝜽𝒓 )
0.629
0.515
0.469
0.325
0.191
0.122
0.743
0.682
0.707
0.731

The light when enters from air to water the ray is deflected towards the normal.

Incidence vs refracted angle
90
80
y = 0.5691x + 3.9729

70

𝜽𝒊

60
50
40
30
20
10
0
0

10

20

30

40

50

60

𝜽𝒓

1

Physics 2 Lab

The angle of incidence and angle of refraction does not obey linear fit. The change in angle of
refraction increase quickly when compared to incident angle especially at higher angle of
incidence. This is quite evident from the data table.
1.2
y = 1.3323x - 4E-05
R² = 0.9999

1

𝐬𝐢𝐧𝜽𝒊

0.8
0.6

0.4
0.2
0
0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

𝐬𝐢𝐧𝜽r

The sine of the angle of incidence and sine of angle of refraction obeys a linear fit.
The slope represents the refractive index
Equation of trendline: y = 0.7596x - 0.0091
Slope: 0.759
Index of refraction of water from Snells law
𝒏𝒂𝒊𝒓 𝐬𝐢𝐧 𝜽𝒊 = 𝒏𝒘𝒂𝒕𝒆𝒓 𝐬𝐢𝐧 𝜽𝒓
𝑅𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑣𝑒 𝑖𝑛𝑑𝑒𝑥 𝑜𝑓 𝑎𝑖𝑟 𝑤𝑖𝑡ℎ 𝑟𝑒𝑠𝑝𝑒𝑐𝑡 𝑡𝑜 𝑤𝑎𝑡𝑒𝑟 =
0.759−0.7518

Percent error=|

0.7518

𝒏𝒂𝒊𝒓
1
=
= 0.7518
𝒏𝒘𝒂𝒕𝒆𝒓 1.33

| × 100 = 0.96%

2

Physics 2 Lab

Part II: Water to Air
The ray of light when travelled from water to air the ray bends away from normal
𝜽𝒊

𝜽𝒓

3
6
10
21
24
34
40
48
42
37

𝐬𝐢𝐧(𝜽𝒊 )

4
8
13
29
33
48
59
82
63
53

0.0523
0.104
0.1736
0.358
0.407
0.559
0.643
0.743
0.669
0.602

𝐬𝐢𝐧(𝜽𝒓 )
0.0697
0.139
0.225
0.485
0.545
0.743
0.857
0.9902
0.891
0.798

Incidence vs refracted angle
90
80
70

𝜽𝒊

60
50
40
30

20
10
0
0

10

20

30

40

50

60

𝜽𝒓

3

Physics 2 Lab

1.2
1

y = 1.3323x - 4E-05

𝐬𝐢𝐧𝜽𝒊

0.8
0.6
0.4
0.2
0
0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

𝐬𝐢𝐧𝜽r

Equation of trendline: y = 1.3323x - 4E-05

Slope:1.3323 which is the refractive index
I...


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