let

f(7)=0

f1(7)=14

g(7)=1

g1(7)=1/7

find h1(7) if h(x)=f(x)/g(x)

LOOK ABOVE ( f1 means prime, like find the derivative at that point)

(Same with g1) It just means find the derivative

f ‘ (7)=14

g ‘ (7)=1/7

find h’ (7) if h(x)=f(x)/g(x)

h’ (x) = [g(x) * f ‘ (x) –f(x)* g’(x)] /(g(x))^{2}

h’ (7) = [g(7) f’(7) –f(7) g’(7)]/(g(7))^{2}

= [1*14-0* 1]/1^{2 } =14

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