x^4 +4x^2y^3+y^2=2y

Find dy/dx

Then evalute at the point (1,-1)

Answer choices are

(a)3

(b)0

(c)undefined

(d)1/2

x^{4} +4x^{2}y^{3}+y^{2}=2y

4x^{3}+8x y^{3}+4x^{2}*3y^{2 }dy/dx+ 2y dy/dx = 2 dy/dx

dy/dx *(12x^{2}y^{2}+2y-2) = (4x^{3}+8xy^{3})

dy/dx = -(4x^{3}+8xy^{3})/ (12x^{2}y^{2}+2y-2)

dy/dx at (1,-1) = -(4-8) /(12-2-2) = 4/8 = 0.5

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