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please solve these 4 questions in Operation Research/Probability
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4Of all 40-year –old women. 1% have breast cancer. If a woman has breast cancer, a
mammogram will give a positive indication for cancer 90% of the time. If a women does not
have beast cancer, a mammogram will give a positive indication for cancer 9% of the time . if a
40-year -old women’s mammogram gives a positive indication for cancer, what is the
probability that she has cancer?
Soution:
Let p be a 40-year-old woman has positive in mammogram, and c be a 40-year-old woman has
breast cancer, then C~ be a 40-year-old woman does not have breast cancer. Then we have P(c)
= 0.01, P(c~) = 0.99, P(p|c) = 0.90, P(p|c~) = 0.09 , we need to find P(c|p). Using Bayes
theorem, we have
P(c|p) = P(p|c)*P(c)/P(p) = P(p|c)*P(c)/(P(p|c)*P(c)+ P(p|c~)*P(c~))
=0.90*0.01/(0.90*0.01+0.09*0.99)
=0.0917
5three out of every 1,000 low – risk 50 –old males have colon, if a man has colon cancer a test
for hidden blood in the stool will indicate hidden blood half the time. If he does not have colon
cancer, a test for hidden blood in the stool will indicate hidden blood 3% of the time. If the
hidden – blood lest turns out positive for a low – risk 50- year -old male, what is the chance that
he has colon cancer
Solution:
Let c be a low-risk 50-old male have colon cancer, then P(c) = 0.003, P(c~) = 0.997. let b be the
event that test indicate the hidden blood in the stool, then P(b|c) =0.5, P(b|c~) = 0.03. We
need to find P(c|b). Using Bayes theorem,
P(c|b) = P(b|c)P(c)/P(b) = P(b|c)*p(c...
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