y = 2x^{4} − 12x^{3} 16x^{2}

^{find solution}

2x^{4} − 12x^{3} +16x^{2}

=2x^{2}(x^{2}-6x+8) = 2x^{2}(x^{2}-4x-2x+8)

2x^{2}(x(x-4)-2(x-4))= 2x^{2}(x-4)(x-2)

x= 0 or x=2 or x=4

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