Write a balanced equation for the combustion of octane (C8H18) Please show how you get this.
Gasoline = C8H18
Oxygen = O2
Carbon dioxide = CO2
Water = H2O
Since 8 of C is involved we must have 8CO2
Since 18 of H is involved we must have 9 H2O
This accounts for 8*2 +9 =25 of Oxygen which is 12.5 O2
C8H18+12.5 O2 = 8CO2+ 9H2O
2C8H18+25O2 = 16CO2+18H2O
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