A plane with constant acceleration until the half of the runway reaches
the 80% of the velocity required for the take off.What fractional part
of the track does it reach the take-off speed?
= distance covered at halfway stage
be covered for takeoff
velocity at halfway stage
= take off
was 80% of takeoff speed)
Dividing (2) by (1)
O.36 * (1.25)²
=s2/s1 (remember v1 was 80% of takeoff speed)
In other words 56.25
% of the distance covered so far is needed for takeoff
of the entire runway
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