The increment and decrement operations In C++

Computer Science
Tutor: None Selected Time limit: 1 Day

  • How increment and decrement operations work with combined assignments (also, look out for cases of integer division) 
Nov 19th, 2014

The increment operator ++ adds 1 to its operand, and the decrement operator -- subtracts 1 from its operand. Thus:

x = x+1;is the same as
 
x++;

And similarly:

x = x-1;is the same as
 
x--;

Both the increment and decrement operators can either precede (prefix) or follow (postfix) the operand. For example:

x = x+1;
 
can be written as++x;// prefix form

or as:

x++;// postfix form

When an increment or decrement is used as part of an expression, there is an important difference in prefix and postfix forms. If you are using prefix form then increment or decrement will be done before rest of the expression, and if you are using postfix form, then increment or decrement will be done after the complete expression is evaluated.

Example:

Following is the example to understand this difference:

#include<iostream>usingnamespace std;
 
main(){int a =21;int c ;// Value of a will not be increased before assignment.
   c = a++;   
   cout <<"Line 1 - Value of a++ is :"<< c << endl ;// After expression value of a is increased
   cout <<"Line 2 - Value of a is :"<< a << endl ;// Value of a will be increased before assignment.
   c =++a;  
   cout <<"Line 3 - Value of ++a is  :"<< c << endl ;return0;}

When the above code is compiled and executed, it produces the following result:

Line1-Value of a++is:21Line2-Value of a is:22Line3-Value of ++a is:23

Nov 19th, 2014

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Nov 19th, 2014
...
Nov 19th, 2014
Dec 6th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer