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i am stuck on the following problem. here is a pic of the problem
any help would be appreciated
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Explanation & Answer
2x^2 - 1 = 11x
2x^2 - 11x - 1 = 0
Now using quadratic formula then
x = (- b ± √b^2 - 4ac)/2a
Now
x = (- (-11) ± √(-11)^2 - 4(2)(-1)) / 2(2)
x = ( 11 ± √121 + 8) / 4
x = ( 11 ± √129) / 4
Hence the roots are x = { (11 + √129)/4 , (11 - √129)/4 }
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