college algebra function problems6

Mathematics
Tutor: None Selected Time limit: 1 Day

i am stuck on the following problem. here is a pic of the problem

http://imgur.com/87mTQh6

any help would be appreciated

Nov 19th, 2014

2x^2 - 11x = 1

2x^2 - 11x  - 1 = 0

Now using quadratic formula then

x = (- b ± √b^2 - 4ac)/2a

Now

x = (- (-11) ± √(-11)^2 - 4(2)(-1)) / 2(2)

x = ( 11 ± √121 + 8) / 4

x = ( 11 ± √129) / 4

Hence the roots are  x = { (11 + √129)/4 , (11 - √129)/4 }

Nov 19th, 2014

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Nov 19th, 2014
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Nov 19th, 2014
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