if the coordinates of point A are (sqrt 2/2, sqrt 2/2)
Point A ( sqrt 2/2 , sqrt 2/2)now sqrt 2/2 = sqrt 2/ (sqrt 2* sqrt 2) = 1/sqrt 2therfore , Point A (1/sqrt 2, 1/sqrt 2)now sin theta = x = 1/sqrt 2 and cos theta = y = 1/sqrt 2we know for cos 45 = sin 45 = 1/sqrt 2
so the value of theta here is 45 degree .Please bestest my answer if helpful :)
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