Sqrt(16+x^{2})/3+ (7-x)/4 = 8/3

Sqrt(16+x^{2})/3 = (x/4-7/4+8/3) = 3x/12-21/12+32/12 =(3x+11)/12

4 sqrt(16+x^{2})= (3x+11)^{2}

16 (16+x^{2}) = 9x^{2}+66x+121

7x^{2}-66x+256-121=0

7x^{2}-66x+135 =0

7x^{2}-21x-45x+135=0

7x(x-3)-45(x-3) =0

(x-3)(7x-45)=0

X= 3 or x= 45/7

X= 3 is admissible

He walks (7-x) = 4 miles.

Further he has to go vertical 3 miles

AP = sqrt(4^{2}+3^{2}) =5

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up