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Explanation & Answer
Kindly see attached the requested file containing:- Answer to the prelab questions for the oscilloscope lab- Revised data with the correct calculations. I've also corrected table 1 since you had clearly exchanged the data for the two lenses by comparing the results in the rest of tables- Answer to the postlab questions for the focal lenses labAdditionally, I have included a plagiarism report in case you need to present it. In that case, though, I would suggest you to change the question into private to ensure that your teacher cannot trace you back here.
PHYSICS LABORATORY REPORT
(Name)
(Course)
(Date)
Laboratory 38: Oscilloscope measurements
1.
An electron gun or electron emitter is the source of electrons in the cathode ray tube. Basically, it
is formed of three different components:
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The cathode, from which electrons are emitted. This cathode differs from any other type
of cathode as the ones commonly used in electrochemistry in that emission of electrons
happens as a consequence of the high temperature of the cathode. Taking this into
account, the cathode is generally referred to as a “hot cathode” or “thermoionic cathode”.
The anode, towards which the electrons emitted by the cathode will be directed.
A series of electrical plates that will help in focusing the electron beam emitted from the
cathode. In the case of the cathode ray tube, these set of plates is commonly referred to
as “Wehnelt cylinder”.
2.
In order to obtain a linear timescale in the oscilloscope, we will need to apply a linear wave at the
horizontal plates of the cathode ray tube. However, and since it will be a wave despite of being
linear, the practical shape will be as follows:
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At t = 0 ms, the voltage will be equal to 0
At t = T ms, the voltage will be equal to the maximum desired voltage VT
For t (0, T), the voltage will linearly increase from 0 to VT.
Immediately after t = T, the voltage will instantaneously go back to 0 and the next wave
will start.
Taking this voltage pattern into account, we would obtain a voltage waveform as the one
represented in the image:
3.
Generally, the lifetime of the phosphorescence excited electronic state ranges from 1 μs to 10 s
and this time depends on the phosphorescent compound responsible from the emission of the
phosphorescence radiation.
The process by which the phosphor glow appears is during the emission of phosphorescence when
the electronically excited material present in the fluorescent screen relaxes back to the ground
electronic state. Taking into account that it has been excited by the electron beam that has
stricken the fluorescent screen and that as long as it is striking it the phosphorescence signal will
be constant (since new atoms are continuously being excited and relaxed through the emission of
phosphorescence radiation), I expect that the phosphor glow will last until around 10 seconds
after the electron beam has stopped striking the fluorescent screen of the CRT.
4.
The number of complete cycles that will be shown in the oscilloscope is c...