One number exceeds another number by 5. if the sum of the two numbers is 39, what is the smaller number
Your 2 equations are:
x-y = 5 (because one number exceeds the other by 5. Therefore the difference is 5)
x+y = 39 (The sum of the two numbers is 39)
Solve one of the equations for one variable. I'm going to solve x - y = 5 for x.
x - y = 5 --> x = 5 + y
Now substitute 5 + y into the second equation for x.
x+y = 39
(5+y) + y = 39
5 + 2y = 39
2y = 34
y = 17
Now, you can solve for x by plugging y into one of the equations:
x - y = 5
x - 17 = 5
x = 22
Therefore, the smaller number is 17.
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