How do i figure grams of oxygen are in 3.81*10^23 units of (NH4)2SO4?
3.81 x 10^23 units of (NH4)2SO4 - if you divide by 6.02 x 10^23 (Avogadro's number), you'll get the number of moles of (NH4)2SO4.
3.81 x 10^23 units (NH4)2SO4* (1 mol / 6.02 x 10^23) = 0.63 moles of (NH4)2SO4
We need a mass percent of oxygen.
The molecular weight of (NH4)2SO4 is
2(Nitrogen) + 8(Hydrogen) + 1(sulfur) + 4(Oxygen)
2(14) + 8 + 32 + 4(16) = 132
The molecular weight of oxygen in the compound is 4*16 = 64
The mass percent of oxygen is: 64/132 = 0.48 (48%)
If we multiply the mass percent of oxygen by the moles of (NH4)2SO4 - we'll know how many moles of oxygen we need:
0.63 moles (NH4)2SO4 * (0.48) = 0.302 moles of oxygen
Convert moles of oxygen to grams:
0.302 moles Oxygen (16 g /mol ) = 4.84 g Oxygen
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?