With this function, I just need help on finding the points. Not graphing it

label Algebra
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Nov 24th, 2014

Here, F(x)=(x+3)^5

Let y=f(x)
so y=(x+3)^5

now put values pf x and find the value of y,
like x=0,y=(0+3)^5 = 243, so the point is (0,243)
putting x=-3, y=(-3+3)^5 = 0^5 =0, so the point is (-3.o)

similarly, for x=3, y=(3+3)^5=6^3 = 776.


Hope this helps :)

Please best my answer if it was helpful. Please message me if you need further help :)

Nov 24th, 2014

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Nov 24th, 2014
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Nov 24th, 2014
Jun 28th, 2017
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