N2(g) + O2(g) <========> NO(g).
If [N2] = 0.520 M, [O2]
= 0.0662 M, and [NO] = 0.00956 at equilibrium, what is the value of K?
The reaction should be written as at balance:
N2(g) + O2(g) <========> 2 NO(g)
So the Equilibrium constant K=[NO]^2/[N2][O2]
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