Chemistry help with homework

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N2(g)     +   O2(g) <========>  NO(g).

 If [N2] = 0.520 M, [O2] = 0.0662 M, and [NO] = 0.00956 at equilibrium, what is the value of K?

Nov 24th, 2014

The reaction should be written as at balance:

N2(g)  +  O2(g) <========> 2 NO(g)

So the Equilibrium constant K=[NO]^2/[N2][O2]

Therefore, 

K=0.00956^2/(0.52x0.0662)=2.65x10^-3

Nov 24th, 2014

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