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college Chemistry 102

Chemistry
Tutor: None Selected Time limit: 1 Day

trying to figure out how much heat (in kj) must be added to raise the temp of H20 by 3.23 deg. C

Nov 25th, 2014

Heat added = (specific heat x temp difference) per gram

So (4.18 x 3.23) = 13.50 j =. 0.0135 kj

Answer 0.0135 kj per gram of water

Nov 25th, 2014

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