Time remaining:
college Chemistry 102

Chemistry
Tutor: None Selected Time limit: 1 Day

trying to figure out how much heat (in kj) must be added to raise the temp of H20 by 3.23 deg. C

Nov 25th, 2014

Heat added = (specific heat x temp difference) per gram

So (4.18 x 3.23) = 13.50 j =. 0.0135 kj

Answer 0.0135 kj per gram of water

Nov 25th, 2014

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Nov 25th, 2014
...
Nov 25th, 2014
Dec 5th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer