just doing homework

(xy + 3x + 2) + (3x^2 + y)

Opening the brackets, we get

= xy + 3x + 2 + 3x^2 + y

Now

= 3x^2 + 3x + 2 + xy + y

= 3x^2 + 3x + 2 + y(x + 1)

= 3x(x + 1) + y(x + 1) + 2

= (x + 1)[3x + y + 2]

Hence (xy + 3x + 2) + (3x^2 + y) = (x + 1)[3x + y + 2]

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