A pharmacist has a 10% alcohol solution and a 25% alcohol solution. How many milliliters of each solution will she need in order to have 200 mL of a 20% alcohol solution?
Assuming the volume of the alcohol solution is addable, and x ml 10% alcohol solution is needed,
10% x + 25% (200-x) = 20% * 200
10x + 25 *200-25x=20*200
So 67ml 10% alcohol solution is needed, and 200-67=133ml 25% alcohol solution is needed.
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