7. A building of height h is observed from two points, P and Q, that are
105.0 m apart as shown. The angles of elevation at Pand Q are 400 and 320,
respectively. Calculate the height, h, to the nearest tenth of a metre.
x/y = tan 400
y = x * cot 400
x/(105-y) =tan 320
105-y =x cot 320
105 = y+x cot 320= xcot 400+x cot 320
x = 105/(cot 400+cot
x = 105/(cot 400+cot 320)
x = 105 /(1.191754+1.600335)= 105/2.792088
x = 37.60626
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?