7. A building of height h is observed from two points, P and Q, that are

105.0 m apart as shown. The angles of elevation at Pand Q are 400 and 320, respectively. Calculate the height, h, to the nearest tenth of a metre. P 1050m

x/y = tan 40^{0}

y = x * cot 40^{0}

x/(105-y) =tan 32^{0}

105-y =x cot 32^{0}

105 = y+x cot 32^{0}= xcot 40^{0}+x cot 32^{0}

x = 105/(cot 40^{0}+cot 32^{0})

x = 105 /(1.191754+1.600335)= 105/2.792088

x = 37.60626

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