with mean of 100 and standard deviation of 18. Researcher modifies test and gives test to 36 kids. Average test score is 104A. Null hypothesis?
B. Standard error?
C. Calculate z
D. Reject or accept null hypothesis?
E. What does your conclusion mean?
Null hypohesis H0: mu =100
Standard error =18/sqrt(36) =18/6=3
z= (xbar-mu)/standard error = (104-100)/3 =4/3= 1.33
Since |z| < 1.96 (5% value), we do not reject the null hypothesis
The test scores follow a normal distribution with mean 100
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