with mean of 100 and standard deviation of 18. Researcher modifies test and gives test to 36 kids. Average test score is 104A. Null hypothesis?

B. Standard error?

C. Calculate z

D. Reject or accept null hypothesis?

E. What does your conclusion mean?

Null hypohesis H0: mu =100

SD =18

n=36

Standard error =18/sqrt(36) =18/6=3

z= (xbar-mu)/standard error = (104-100)/3 =4/3= 1.33

Since |z| < 1.96 (5% value), we do not reject the null hypothesis

The test scores follow a normal distribution with mean 100

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