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A study of 100 kids with history of group part. is given a survey..

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the majority of the kids have scores that form a normal distribution with a mean of 50 and SD of 15. The sample has average of 53.8. Conduct 2-tail test with a=0.05.

A. Null hypothesis?
B. Standard error?

C. Calculate z

D. Cohen's d?

Nov 26th, 2014

xbar = 53.8

mu =50

null hypothesis H0 : mu =50

SD =15

Standard error =15/sqrt(100)=15/10=1.5

z= (xbar-mu)/standard error = (53.8-50)/1.5 = 3.8/1.5 = 7.6/3 =2.533

|z|>1.96, we reject the null hypothesis.

The mean of test scores is not 50 

Cohen's d is for two populations.

d =(mean difference)/SD

d=(53.8-50)/15 =3.8/15 =0.2533

Nov 26th, 2014

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