f(t), which represents the number of hours of daylight t days into the year: f(t)=11+2.2sin((2pie/365)t-1.25). . How many hours of daylight are there on the tenth day of the year? Round the answer to the nearest tenth.
Plug in 10 for t:
f(10) = 11 + 2.2sin((2pi/365)*10-1.25)) = 9.1 hours of daylight
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