f(t), which represents the number of hours of daylight t days into the year: f(t)=10+2.8sin((2pie/365)t-1.35) . How many hours of daylight are there on the 100th day of the year?
Plug in 100 into f(t):
f(100) = 10 + 2.8*sin((2*pi/356)*100-1.35) = 11.1 hours of daylight
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