Stuck on part 1,2, and 3! Image Below

Physics
Tutor: None Selected Time limit: 1 Day

Nov 30th, 2014

1. Considering the green dash line is x axis, and the perpendicular line to x green dash line would be y axis. 

Then for force 1, F1=438 N, 

F1x=438cos10=438x0.985=431 N,   F1y=438sin10=438x0.174=76 N

For force 2, F2=358 N

F2x=358cos(-31)=358x0.857=307 N,  F2y=358sin(-31)=358x-0.515=-184 N

For the resultant of these two force, F

Fx=F1x+F1y=431+307=738 N, Fy=F1y+F2y=76-184=-108 N

Therefore the magnitude of F =(Fx^2+Fy^2)^1/2= 746 N

2. Sin(Theta)=Fy/F=-108/746=-0.145

    Theta=-8.3

So the direction of the force is -8.3 degree to the positive x axis.

3. F=ma,

    a=F/m= 746/3693 N/kg=0.202 N/kg=0.202 m/s2

So the acceleration is 0.202 m/S2


Nov 30th, 2014

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Nov 30th, 2014
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Nov 30th, 2014
Dec 5th, 2016
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