Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.

Chemistry
Tutor: None Selected Time limit: 1 Day

Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.85.

a) What is the fuel to air ratio on a volume basis for this reaction?

Nov 30th, 2014

Composition of air:

N2: 78.08%

O2: 20.95%

Argon: 0.93%

CO2: 0.03%

Others: 0.01%

Water vapor: variable

For simplicity, air is considered as a mixture that contains 79% N2 and 21% O2 only. Other components are neglected.

0.21O2 + 0.79N2 = 0.21(O2 + 3.76N2)

If oxygen is contained in the fuel, the amount of air required to oxide the fuel is reduced due to the presence of oxygen in the air fuel mixture.

CH3OH + 1.5(O2 + 3.76N2) → CO2 + 2H2O + 5.64N2

On a molar basis, the ratio of fuel to air is  [1/(3.76+5.64)] = 1/59.5 = 0.1067.

Please chose it as a best answer. Thx

Nov 30th, 2014

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Nov 30th, 2014
...
Nov 30th, 2014
Dec 8th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer