​b) What is the fuel to air ratio on a mass basis for this reaction?

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Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.85. 

b) What is the fuel to air ratio on a mass basis for this reaction?


Nov 30th, 2014

To find the ratio on a mass flow basis, which is the way in which the aeroengine industry discusses it, we need to ``weight'' the molar proportions by the molecular weight of the components. The fuel molecular weight is32 g/mol, the oxygen molecular weight is32 g/moland the nitrogen molecular weight is (approximately)28 g/mol. The fuel/air ratio on a mass flow basis is thus:

Fuel-air ratio = =0.132


Nov 30th, 2014

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Nov 30th, 2014
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