​b) What is the fuel to air ratio on a mass basis for this reaction?

Chemistry
Tutor: None Selected Time limit: 1 Day

Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.85. 

b) What is the fuel to air ratio on a mass basis for this reaction?


Nov 30th, 2014

To find the ratio on a mass flow basis, which is the way in which the aeroengine industry discusses it, we need to ``weight'' the molar proportions by the molecular weight of the components. The fuel molecular weight is32 g/mol, the oxygen molecular weight is32 g/moland the nitrogen molecular weight is (approximately)28 g/mol. The fuel/air ratio on a mass flow basis is thus:

Fuel-air ratio = =0.132


Nov 30th, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Nov 30th, 2014
...
Nov 30th, 2014
May 29th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer