d) Considering only the major species and assuming complete combustion, what is

Chemistry
Tutor: None Selected Time limit: 1 Day

Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.85. 

d) Considering only the major species and assuming complete combustion, what is the composition (in mole fractions) of each species in the combustion products?

Nov 30th, 2014

Consider the combustion of methanol (CH3OH) in air at an equivalence ratio of 0.85. 

d) Considering only the major species and assuming complete combustion, what is the composition (in mole fractions) of each species in the combustion products?

Answer:

According to the reaction:

CH3OH + 1.5(O2 + 3.76N2) → CO2 + 2H2O + 5.64N2

                                                   1 mol    2 mol     5.64 mol

So the mol total = 5.64+ 1 + 2 = 8.64 mol

Mole fraction of CO2 = 1 mol / 8.64 mol = 0.115

Mole fraction of H2O = 2 mol / 8.64 mol= 0.231

Mole fraction of N2 = 5.64 / 8.64 mol = 0.652


Nov 30th, 2014

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Nov 30th, 2014
...
Nov 30th, 2014
Mar 24th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer