solve for t

6t^(-1/3)*2 - t^(-1/3)-1 =0

let t^(-1/3)=y

6y^2-y-1=0

6y^2-3y+2y-1=0

3y(2y-1)+1(2y-1)=0

(2y-1)(3y+1) =0

2y-1=0 or 3y+1=0

y=1/2 or y=-1/3

t^(-1/3)=1/2 or t^(-1/3)=-1/3

Taking power -3 both side , we get

t=(1/2)^(-3) or t=(-1/3)^(-3)

t=2^(3) or t= -3^(3)

t=8 or t=-27

I hope, it will really helpful for you.

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