Blood type AB is found in only 3% of the population†. If 240 people are chosen at random, find the probability of the following. (Round your answers to four decimal places.)
Since the population is large, we can use the normal approximation to the Binomial
with P(success)=p =0.03
Expected number of people with AB blood group = 240 * 0.03 =7.2
and standard deviation √ np(1-p) = √ 240 (0.03)(0.97)
Hence z-score = (5 – 7.2) ÷ 2.6427
P(more than 5 will have AB blood group) = P(z ≥ -0.8325)
= 1- 0.2026
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