I need to find the definite integral. I do not know how to type the integral sign. But the number on top is 4 and the number on bottom is 0. and the equation is (3x^2-2)^2xdx

The Definite Integral, from 1 to 2, of 2x dx:

The Indefinite Integral is: ∫2x dx = x^{2} + C

Subtract:

2^{2} + C − 1^{2} − C

4 − 1 + C − C = 3

And "C" gets cancelled out ... so with Definite Integrals we can ignore C.

In fact we can give the answer directly like this:

Yes, it has an area of 3.

(Yay!)

:

^ There an example that can help you solve the question :)

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