I need to find the definite integral. I do not know how to type the integral sign. But the number on top is 4 and the number on bottom is 0. and the equation is (3x^2-2)^2xdx
The Definite Integral, from 1 to 2, of 2x dx:
The Indefinite Integral is: ∫2x dx = x2 + C
22 + C − 12 − C
4 − 1 + C − C = 3
And "C" gets cancelled out ... so with Definite Integrals we can ignore C.
In fact we can give the answer directly like this:
Yes, it has an area of 3.
^ There an example that can help you solve the question :)
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