loga(x-1) - loga(x+6) = loga(x-2) - loga(x+3)

I am stuck at the part when I put them in a division equation: x-1/x+6 = x-2/x+3

(x-1)/(x+6) = (x-2)/(x+3)

Both sides multiply (x+3)(x+6)

(x-1)(x+3)=(x-2)(x+6)

x^2+2x-3=x^2+4x-12

2x-3=4x-12

12-3=4x-2x

9=2x

x=9/2

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