loga(x-1) - loga(x+6) = loga(x-2) - loga(x+3)
I am stuck at the part when I put them in a division equation: x-1/x+6 = x-2/x+3
(x-1)/(x+6) = (x-2)/(x+3)
Both sides multiply (x+3)(x+6)
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