Write a balanced equation for the combustion of pentane, C5H12, in oxygen, , forming the products carbon dioxide, and water, H2O. How many grams of carbon dioxide will be produced by the complete reaction of 6.08 grams of pentane?
How many grams of CO2 will be produced by the complete reaction of 6.08 grams of pentane?
First you would need to find the molar mass of pentane (12x5 +12 =72 g/mol), then you would you divide the two values (6.08 g C5H12/ 72 g/mol = 0.084 mols C5H12). You would then need to figure out the moles of CO2 by comparing coefficients and multiplying (0.084 mols C5H12 x 5/1= 0.422 mols CO2 **[when doing this, you always multiply the number of mols by the coefficient in front of the substance you're trying to get the mols of/the coefficient of the original substance]**). After you find the mols, you would multiply by the molar mass of the new substance (12+ 32=44 g/mol) (44 g/mol x 0.422 mols CO2 = 18.57 g CO2).