label Chemistry
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Write a balanced equation for the combustion of pentane, C5H12, in oxygen, , forming the products carbon dioxide, and water, H2O. How many grams of carbon dioxide will be produced by the complete reaction of 6.08 grams of pentane?

Dec 4th, 2014

C5H12+ 8O2 ----> 5CO2 + 6H2O

How many grams of CO2 will be produced by the complete reaction of 6.08 grams of pentane?

First you would need to find the molar mass of pentane (12x5 +12 =72 g/mol), then you would you divide the two values (6.08 g C5H12/ 72 g/mol = 0.084 mols C5H12). You would then need to figure out the moles of CO2 by comparing coefficients and multiplying (0.084 mols C5H12 x 5/1= 0.422 mols CO2 **[when doing this, you always multiply the number of mols by the coefficient in front of the substance you're trying to get the mols of/the coefficient of the original substance]**). After you find the mols, you would multiply by the molar mass of the new substance (12+ 32=44 g/mol) (44 g/mol x 0.422 mols CO2 = 18.57 g CO2).

Dec 4th, 2014

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Dec 4th, 2014
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Dec 4th, 2014
Oct 18th, 2017
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