According to the following reaction: Zn(s) +Cl2(g) --> ZnCl2(s) What is the theoretical yield, in grams, of ZnCl2(s) if 39 grams of zinc were allowed to react with excess chlorine? Enter your answer in scientific notation.

If Zn were allowed to react with excess Cl2, then Zn will be completely consumed.

Given that the molar mass of Zn is 65g/mol

39 g Zn=39/65 =0.6 mol Zn

Since 1 mol Zn can convert to 1 mol ZnCl2, 0.6 mol Zn will produce 0.6 mol ZnCl2.

The molar mass of ZnCl2=65+35.5x2=136 g/mol

So the theoretical yield of ZnCl2 will be 0.6x136=81.6 g

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