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Help with Statistics Problem9

Algebra
Tutor: None Selected Time limit: 0 Hours

Find the range and the standard deviation (correct to two decimal places).

80, 94, 100, 100, 101
the range is already 21 but what is the standard deviation?


Dec 4th, 2014

range = 101-80= 21

mean = (80+ 94+ 100+ 100+ 101)/ 5= 475/5 = 95

SD = sqrt(((80-95)^2+(94-95)^2+(100-95)^2+(100-95)^2+(101-95)^2) / 5)

      = sqrt ( (225+1+25+25+36)/5)

      = sqrt ( 312/5)

     = sqrt (62.4)

    = 7.899 or 7.90

Dec 4th, 2014

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