According to the following reaction: Zn(s) +Cl2(g) --> ZnCl2(s) What is the theoretical yield, in grams, of ZnCl2(s) if 108 grams of zinc were allowed to react with excess chlorine? Enter your answer in scientific notation.

For this, you have to find the molar mass of both Zn (65.38) and ZnCl2 (65.38 + (2 x 35.45) = 136.28). Because there is excess chlorine, the 108 g of ZnCl2 is the limiting factor. so 108/65.38 = 1.65 moles of Zn. Then multiply this by the molar mass of your product, ZnCl2. So 1.65 x 136.28 = 224.86 g of ZnCl2 (s). In scientific notation, this is 2.2486 x 10^2 g