#59-62

Chemistry
Tutor: None Selected Time limit: 1 Day

Dec 8th, 2014

59.  Ammonia molar mass is 17. So in 76.1 g you have 76.1/17 = 4.48 mol ammonia.

60.  1 mole has 6.02 x 10^23 molecules, so 10.8 mole has 10.8 x 6.02 x 10^23  = 6.5 x 10^24 molecules

61.  1 mole has 6.02 x 10^ 23 molecules. so 7.21 x 10^21 molecule = 0.012 mol Na2 CO3

      Now molar mass of Na2CO3 is 83.  Therefore 0.012 mole has mass = 0.012 x 83 = 0.98 g

62. Molar mass of Helium is 4.0, so 50 g Helium has 50/4 = 12.5 mole.

    Now mole volt. of Helium is 22.4 L/Mol. So 50 g of Helium has 12.5 x 22.4 = 280 L of Helium

Dec 8th, 2014

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