# ASTR 112 Grossmont Analyzing Motion of Objects in Free Fall With Video Lab Report

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astr 112

Grossmont College

ASTR

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Grossmont College Gravity Laboratory
1.

It is observed that the keys and ball are falling at the same rate(acceleration) regardless of their
size and shape, but crumpled paper floats down constantly. The difference is, due to the air
resistance (drag) exerted, the keys appear to fall faster than the other two objects. The
crumbled paper is the slowest among the three to fall, due to greater air resistance.

2.

The keys take 64 frames to fall, whereas the ball takes 65 frames, and crumbled paper takes 67
frames to fall.

3.

Duration tf of object’s fall =
𝑁𝑢𝑚𝑏𝑒𝑟𝑜𝑓𝑓𝑟𝑎𝑚𝑒𝑠𝑏𝑒𝑡𝑤𝑒𝑒𝑛𝑟𝑒𝑙𝑒𝑎𝑠𝑖𝑛𝑔𝑡ℎ𝑒𝑜𝑏𝑗𝑒𝑐𝑡𝑎𝑛𝑑𝑖𝑚𝑝𝑎𝑐𝑡
𝐹𝑟𝑎𝑚𝑒𝑟𝑎𝑡𝑒(𝐹𝑃𝑆)

Duration tf of keys’ fall =

64

{as we are using 60FPS video)

60

= 1.066 second

Duration tf of ball fall =

65

{as we are using 60FPS video)

60

= 1.083 second

Duration tf of paper fall =

67

{as we are using 60FPS video)

60

= 1.116 second
4. Average speed vav = (total distance covered) divided by (time
taken)
Average speed =

𝑡𝑜𝑡𝑎𝑙𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒𝑐𝑜𝑣𝑒𝑟𝑒𝑑
𝑡𝑖𝑚𝑒𝑡𝑎𝑘𝑒𝑛

So, average speed of keys =

𝐻
𝑡𝑖𝑚𝑒𝑡𝑎𝑘𝑒𝑛𝑏𝑦𝑘𝑒𝑦𝑠

=
Average speed of ball =

5.6𝑚
1.066𝑠

{given, H =5.60m}

= 5.253 m/s

𝐻
𝑡𝑖𝑚𝑒𝑡𝑎𝑘𝑒𝑛𝑏𝑦𝑘𝑒𝑦𝑠

=
Average speed of paper =

5.6𝑚
1.083𝑠

= 5.170 m/s

𝐻
𝑡𝑖𝑚𝑒𝑡𝑎𝑘𝑒𝑛𝑏𝑦𝑘𝑒𝑦𝑠

=

5.6𝑚
1.116𝑠

= 5.017 m/s

5. For a constant acceleration from 0 m/s, final (impact) speed vf = 2vav
For keys, impact speed, vf = 2(vav for keys)
= 2 ( 5.253 m/s) = 10.506 m/s
For ball, impact speed, vf = 2(vav for ball)
= 2 ( 5.170 m/s) = 10.34 m/s
6. The acceleration g (= change in speed / time taken) =
For keys(vertical), g

= 10.506
= 9.8 m/s2
1.066

For keys(sideways), g
For ball, g

= 10.506
= 9.72 m/s2
1.080

= 10.34
= 9.6 m/s2
1.083

7. The average value of g= (9.8+9.72+9.6)/3
= 9.70 m/s2...

### Review

Anonymous
Very useful material for studying!

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