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Help with Algebra Question7

Algebra
Tutor: None Selected Time limit: 0 Hours

Find the range and the standard deviation (correct to two decimal places).

83, 93, 96, 99, 99
range
standard deviation
Dec 9th, 2014

mean=(83+93+96+99+99)/5=94

(83-94)^2=121, (93-94)^2=1, (96-94)^2=4, (99-94)^2=25

SD=[(121+1+4+25+25)/5]^1/2=(176/5)^1/2=5.93

range=99-83=16

Dec 9th, 2014

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Dec 9th, 2014
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Dec 9th, 2014
Dec 4th, 2016
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