solving algebra 2 problems
Mathematics

Tutor: None Selected  Time limit: 1 Day 
solve x^9 divided by x^7x+10 = 2x^8x+6 divided by x^9x+10 +3
I'm inferring that your equation is (x^9)/(x^7)(x + 10) = (2x^8)(x + 6)/(x^9)(x +10) +3
If this is the case then first you need to use the property of exponents, which makes (x^9) = 1/x^9 and (1/x^7) = x^7 and (2x^8) becomes 1/(2x^8)
Your equation now looks like this: (x^7)/(x^9)(x+10) = (x+6)(x^9)/(2x^8)(x+10) +3
Now you can crosscancel x's.
1/(x^2)(x+10) = (x+6)(x)/2(x+10) +3
now multiply both sides by 2(x+10)(x^2) to cancel your denominators
2 = (x+6)(x)(x^2) +3
1 = (x+6)(x)(x^2)
now distribute
1 = x^4 + 6x^3
+1 +1
x^4 + 6x^3 +1 = 0
you can then split 6x^3 into 3x^3 + 3x^3
x^4 + 3x^3 + 3x^3 +1 = 0 Notice: since there is an x with a power of 4, there will be 4 solutions.
Using the grouping method:
x^3(x+3)(3x^3 + 1) = 0
x^3 = 0 or x+3 = 0 or 3x^3 +1 = 0
x=0 or x=3 or 3x^3 = 1
x^3 = (1/3)
x = 3rd power SQRT(1/3)
When you have a negative SQRT, you seperate it into SQRT1 and SQRT3
then SQRT1 becomes i
x= (+or) i(3rd powerSQRT3)/3
So the solutions are x=0,3,i(3rdpowerSQRT3)/3, i(3rdpowerSQRT3)/3
Hope this helps! If it does please mark it as best answer! Thanks:)
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