Calculate the mass of solute in the following K3PO4 solution: 2.63×10-1 L of a 1.35×10-3-M solution.
Calculate the volume of 2.59×10-3-M NaClO4 solution needed to provide 8.47×10-2 g of NaClO4.
Calculate the mole of K3P04
MW of K3PO4 = 211.9 g/mol
2.63x10^-1 X 1.35x10^-3 = 3.55x 10^-4 mole
3.55x 10^-4 mole x MW ( 211.9 g/mole) =
mass of K3PO4 = 0.075 g
MW of NAClO4 = 122.44 g/mol
2.59x 10^-3 mole/L X 122.44 g/mol = 0.317 g/L
Vol needed to make .0847 g NaClO4 = 0.317 g/ 1L X = 0.847 g
Multiply both sides by 1L = 1L X 0.317 g/ 1L X = 0.847 g X 1L
Divide boths sides by 0.317 g: 0.317 g /0.317 g X = 0.847 g 1L/0.317g
X = 2.71 L
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