I have been stuck on this question for about an hour, please help.

and 19.0 atm?

First we have to find its new volume using

P1V1/T1 =P2 V2/T2

Hence V1/V2 = P2T1 /(P1T2) (temp in degrees K)

= 19 x 273.15/ 1 x 298.15

=17.4068

now mass has not changed and mass =volume x density

Hence V1 d1= V2 d2

d2 = V1d1/V2 = V1/V2 x d1

= 17.4068 x 3.68

=64.79 g/l

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